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One mole of compound A, with vapor pressure 420mmHg at 50°C, mixed with 5 moles of compound B, with vapor pressure 480mmHg at 50°C to form a homogeneous solution. What is the vapor pressure of mixture at 50°C?

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Answer:

the vapor pressure of mixture at 50°C is 470 mm of Hg

Step-by-step explanation:

The computation of the vapor pressure is shown below:

= (420 × 1 + 480 × 5) ÷ (1 + 5)

= (420 + 2400) ÷ (6)

= 2820 ÷ 6

= 470mm of Hg

Hence, the vapor pressure of mixture at 50°C is 470 mm of Hg

The same would be considered

User Giorgos Dimtsas
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