Question

What is an
equation of the line that passes through the points (-4,-4) and (4, 6)?

Answer 1

Explanation:

1.) Find the slope

`(y_2-y_1)/(x_2-x_1) = (6-(-4))/(4-(-4))= (6+4)/(4+4) = (10)/(8)=\frac{5}4}` = m

2.) Use the slope-point form for a line

`y-y_0=m(x-x_0)`

Pick any point (-4,-4) or (4,6) into
`y_0 and x_0\\`

but your equation is y= 5/4x+1