138k views
4 votes
Given: m∠AKB = 25°

KO = 25

Find: V, Surface Area of of a cone

Please leave answers in term of Pi

User Sjamaan
by
5.0k points

1 Answer

2 votes

Answer:

V = 255.98189 pi

SA = 172.64114π

Explanation:

The first thing to do is find the radius.

the measure of angle AKO = 1/2 the measure of angle AKB

m< AKO = 12.5 degrees

Now use trig to find AO (aka the radius)

tan(12.5) = AO/25

AO = 25* tan(12.5)

I'm leaving it like this to get a more accurate number

Now to find the volume

the volume of a cone is pir^2h/3

plugging everything in we get:

pi(25*tan(12.5))^2 * 25/3

which is about 255.98189 pi

Now for surface area

(this is the moment I realize symbols exist)

SA = πr(r+√h²+r²)

plugging everything in we have

π(25tan(12.5))((25tan(12.5)+√625+(25tan(12.5))^2)

I know it looks like a lot but that's mainly because I left the radius as 25tan(12.5)

The Surface Area is about 172.64114π

User Migmaker
by
5.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.