Question

You flip a coin straight up if the coin reaches a high point of 0.25 m above where you released it what was the initial speed?

Answer 1

Answer: 2.21 m/s

Step-by-step explanation:

Given

Coin reaches a height of 0.25 m above the launch point

Suppose u is the initial speed of the coin

Using the equation of motion

`\Rightarrow v^2-u^2=2as\\`

Putting values

`\Rightarrow 0^2-u^2=2* g* s=2* (-9.8)* 0.25\\\Rightarrow u^2=4.9\\\Rightarrow u=2.21\ m/s`

Thus, the initial velocity is 2.21 m/s