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How many moles are in 1.7 x 10^50 particles of Al?

User Szajmon
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1 Answer

6 votes

Answer:

2.8 × 10²⁶ moles Al

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

  • Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

[Given] 1.7 × 10⁵⁰ particles Al

[Solve] moles Al

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

  1. [DA] Set up:
    \displaystyle 1.7 \cdot 10^(50) \ particles \ Al((1 \ mol \ Al)/(6.022 \cdot 10^(23) \ particles \ Al))
  2. [DA] Divide [Cancel out units]:
    \displaystyle 2.82298 \cdot 10^(26) \ moles \ Al

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

2.82298 × 10²⁶ moles Al ≈ 2.8 × 10²⁶ moles Al

User Fizch
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