62.5k views
3 votes
A line contains the points (-6, -4) and (0, 4). What is the equation of this line in slope-intercept form? A. B. C. y = x – 4 D. y = x + 4

User Lamarmora
by
8.9k points

2 Answers

3 votes

Answer:

A

Explanation:

User Marko Jurisic
by
8.0k points
1 vote

Answer:

y = 4/3 x + 4

Explanation:

The general form of the equation of a line is given as

y = mx + c where m is the slope and c is the intercept on the y axis

where the slope m = (y2 - y1)/(x2 - x1)

Hence given the points (-6, -4) and (0, 4)

m = (4 --4) / (0 --6)

= (4+4)/(0+6)

= 8/6

= 4/3

For a line with given points (x1, y1), the equation is given as

y-y1 = m(x-x1)

Hence the equation of this line in slope-intercept form

y - -4 = 4/3(x --6)

y + 4 = 4/3(x + 6)

3y + 12 = 4x + 24

3y = 4x + 24 - 12

3y = 4x + 12

y = 4/3 x + 4

For a line with given points (x2, y2), the equation is given as

y-y2 = m(x-x2)

Hence the equation of this line in slope-intercept form

y-4 = 4/3(x - 0)

multiply through by 3

3y - 12 = 4x

3y = 4x + 12

y = 4/3 x + 4

User Wnm
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories