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The temperature inside a Carnot refrigerator placed in a kitchen at 22 degree Celcius is 2 degree Celcius. The heat extracted from the refrigerator is 89 MJ/h. What power is needed to operate this refrigerator?

User Warvariuc
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1 Answer

5 votes

Answer: 1.79 kW

Step-by-step explanation:

Given

The temperature of the refrigerator is
T_L=2^(\circ)C\approx 275\ K

The temperature of the kitchen is
T_H=22^(\circ)C

COP of the refrigerator is


COP=(T_L)/(T_H-T_L)=\frac{\text{Desired effect}}{\text{Power}}\\\\\Rightarrow COP=(275)/(22-2)=(89)/(P)\\\\\Rightarrow P=(20)/(275)* 89=6.47\ MJ/h\ \text{or}\ 1.79\ kW

User Whittle
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