Question

Question 7: Help Me Please

Answer 1

• QR||TS

QS is the intersector

• <UQT=<QSR(Alternative interior angles)=52°

Similarly

• <UTQ=<URS=42°

Now

Diagonals of parallelogram bisect eachother

`\\ \rm\Rrightarrow 4x+1=5`

`\\ \rm\Rrightarrow 4x=4`

`\\ \rm\Rrightarrow x=1`

Answer 2

m∠UQT = 52°
m∠UTQ = 42°
x = 1

Explanation:

∠UQT is an alternate interior angle of ∠RSQ

Therefore, ∠UQT is 52°

∠UTQ is an alternate interior angle of ∠URS

Therefore, ∠UTQ is 42°

The diagonals of a parallelogram are congruent, so 4x + 1 is 5

• 4x + 1 = 5
• 4x = 4
• x = 1

-Chetan K