Question

What is the equation of a line that is perpendicular to the given line y = 2x - 3 and

passes through the point (-8, 3)?
Oy=-1/2x-1
Oy=-1/2x - 5
Oy = 2x + 7
Oy = 2x + 11

Answer 1

y = -1/2x - 1

Explanation:

Given equation:

y = 2x - 3

Given point: (x1,y1) = (-8,3)

This is in the form of y = mx + c,

so, m1 = 2

If the lines are perpendicular then the product of their slope will be - 1 i.e.

m1 x m2 = -1

2 x m2 = -1

m2 = -1/2

Now, using one point form formula,

y - y1 = m(x - x1)

or, y - 3 = -1/2( x - (-8))

or, y-3 = -1/2(x + 8)

or, y = -1/2x - 4 + 3

or, y = -1/2x - 1

This is the required equation.