Question

What is the volume (in liters) of 1.51 x10^24 molecules of Argon gas at STP?

Answer 1

Moles of Argon:-

• No of molecules/Avagadro's constant
• 1.51×10^24/6.022×10^23=2.5mol

Now

• 1mol of gas contains 22.4L
• 2.5mol contains:-

`\\ \rm\Rrightarrow 2.5(22.4)=56L`

Answer 2

Step-by-step explanation:

The molar volume of a gas at STP (Standard Temperature and Pressure), which is equal to 22.4 liters.

There are 6.02x10^23 molecules in 1 mole of Argon.

So for 1.51x10^24 molecules of Argon, the volume at STP should be

(1.51x10^24 / (6.02x10^23)) * 22.4

= 56.19 liters