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4 votes
Factor completely.
81x^2+180x+100=81x

1 Answer

1 vote

Answer:

There is no solution :/

Explanation:

81x^2+180x+100=81x

Step 1: Subtract 81x from both sides.

81x^2+180x+100−81x=81x−81x

81x^2+99x+100=0

For this equation: a=81, b=99, c=100

81x^2+99x+100=0

Step 2: Use quadratic formula with a=81, b=99, c=100.

x= −b±√b2−4ac/ 2a

x= −(99)±√(99)2−4(81)(100) / 2(81)

x= −99±√−22599/162

So you see... no solution

Hope this helps!

User Bob Gregor
by
7.7k points

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