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How many molecules Na2S are in 3.6g of Na2S
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How many molecules Na2S are in 3.6g of Na2S

User Kassi
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1 Answer

7 votes

Step-by-step explanation:

n=m/M

n= 3.6g/ (22.99×2+32.07) mol/g

n= 0,0461242793 mol

n≈ 0.046 mol

n≈ 4.6 ×10^(-2) mol

User Sandwich
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