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Solve x2 + 8x − 3 = 0 using the completing-the-square method

User Desorder
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1 Answer

3 votes

Answer:


√(19) - 4 \\or\\ - √(19) - 4

Explanation:


x^2+8x-3=0 \Rightarrow x^2+2.4.x+16-19=0\\\Rightarrow (x+4)^2=19 \\Then\\ x+4 = √(19) \Rightarrow x= √(19) - 4 \\or\\x+4 = -√(19) \Rightarrow x= -√(19) - 4

User Alvescleiton
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