Question

Determine the moles of chlorine needed to react with 38.9 of iron (III) chloride.

2 Fe+3 CI, - 2 Feci

Answer 1

Answer: 0.360 moles

Step-by-step explanation:

To calculate the moles :

`\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}`

`\text{Moles of} FeCl_3=(38.9g)/(162.2g/mol)=0.240moles`

The balanced chemical reaction is:

`2Fe+3Cl_2\rightarrow 2FeCl_3`

According to stoichiometry :

2 moles of require = 3 moles of

Thus 0.240 moles of
`FeCl_3` will require=
`(3)/(2)* 0.240=0.360moles` of
`Cl_2`

Thus 0.360 moles of chlorine needed to react to produce 38.9 of iron (III) chloride.