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Need help asap!! please help !!!!!!!!!!!!!!!! PLEASEEEEE MATH

Need help asap!! please help !!!!!!!!!!!!!!!! PLEASEEEEE MATH-example-1
User FreshD
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1 Answer

6 votes

Answer:

11. CK = 66

12. QS = 72

13. CE = 11

14. LJ = 60

Explanation:

Recall: the corresponding side lengths of similar triangles are proportional and the ratio of their side lengths are equal.

11. AB/KL = AC/KC

77/42 = 121/CK (Substitution)

Cross multiply

77*CK = 121*42

77*CK = 5082

CK = 5082/77

CK = 66

12. QR/BQ = QS/CQ

72/32 = (32 + CS)/32 (Substitution)

Cross multiply

32(32 + CS) = 72*32

1024 + 32*CS = 2304

32*CS = 2304 - 1024

32*CS = 1280

CS = 1280/32

CS = 40

QS = 32 + CS = 32 + 40 = 72

13. QS/CE = QR/CD

33/CE = 36/12

33/CE = 3

Cross multiply

3*CE = 33

Divide both sides by 3

CE = 33/3

CE = 11

14. LJ/LU = LK/LV

LJ/10 = 60/10

LJ/10 = 6

LJ = 6*10

LJ = 60

User Leontyev Georgiy
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