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Solve the system of equations

2x+3y= 6
x+y=4

(6,-2)
(-2,6)
(-3, 4)
(0, 2)

Solve the system of equations 2x+3y= 6 x+y=4 (6,-2) (-2,6) (-3, 4) (0, 2)-example-1
User Meire
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1 Answer

6 votes

Answer:

Explanation:

2x+3y= 6 ========================>>> 2x + 3y = 6

x+y=4 ===== times both sides by 2 =====>>> 2x + 2y = 8

==== subtract these two equations ==>> (2x - 2x) + (3y - 2y) = 6 - 8

0x + y = -2

y = -2 so if x + y = 4 plug in -2 where y was

x + (-2) = 4 add 2 to both sides

x = 6

(6,-2)

(-2,6)

(-3, 4)

(0, 2)

User FTW
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