Question

Potassium chlorate decomposes to produce potassium chloride and oxygen gas according to the balanced equation below. If 1.00 g of potassium chlorate decomposes, and 0.500 g of solid potassium chloride is collected, what is the theoretical yield of potassium chloride and the % Yield of potassium chloride

Answer 1

Answer: The theoretical yield of potassium chloride is 0.596 grams and the % Yield of potassium chloride is 83.9%

Step-by-step explanation:

To calculate the moles :

`\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}`

`\text{Moles of} KClO_3=(1.00g)/(122.5g/mol)=0.008moles`

`2KClO_3\rightarrow 2KCl+3O_2`

According to stoichiometry :

2 moles of
`KClO_3` produce= 2 moles of
`KCl`

Thus 0.008 moles of
`KClO_3` will produce=
`(2)/(2)* 0.008=0.008moles` of
`KCl`

Theoretical yield of
`KCl=moles* {\text {Molar mass}}=0.008moles* 74.5g/mol=0.596g`

% yield =
`\frac{\text {Actual yield}}{\text {Theoretical yield}}* 100=(0.500g)/(0.596g)* 100\%=83.9\%`

The theoretical yield of potassium chloride is 0.596 grams and the % Yield of potassium chloride is 83.9%