Question

What is the diameter of a sphere with a volume of 6915\text{ ft}^3,6915 ft 3 , to the nearest tenth of a foot?

Answer 1

Answer: 11.8 ft

Explanation:

Given

Volume of sphere
`V=6915\ ft^3`

Also, the volume of a sphere

`\Rightarrow V=(4)/(3)\pi r^3`

Putting values

`\Rightarrow V=6915=(4)/(3)\pi r^3\\\\\Rightarrow r^3=(6915* 3)/(4\pi)\\\\\Rightarrow r^3=1650.1704\\\Rightarrow r=11.8\ ft`