Question

4.In a hydroelectric power plant, 100 m3/s of water flows from an elevation of 120 m to a turbine, where electric power is generated. The electric power you get out from the 80% efficiency turbine is known to be 50 MW, what is the rate of irreversible loss in the piping system (in MW unit)

Answer 1

The rate of irreversible loss will be "55.22 MW".

Step-by-step explanation:

The given values are:

Elevation,

h = 120 m

Flow of water,

Q = 100 m³/s

Efficiency,

= 80%

i.e,

= 0.8

Efficiency turbine,

= 50 MW

Now,

Without any loss,

The power generated by turbine will be:

⇒
`P=\delta gQh`

On substituting the values, we get

⇒
`=1000* 9.8* 100* 120`

⇒
`=117.72 \ MW`

Power generated in actual will be:

=
`(50)/(0.8)`

=
`62.5 \ MW`

Hence,

Throughout the piping system,

The rate of irreversible loss is:

=
`Power \ generated \ by \ turbine-Power \ generated \ in \ actual`

=
`117.72-62.5`

=
`55.22 \ MW`