Answer:
![0.7308](https://img.qammunity.org/2022/formulas/mathematics/college/l89t03qyzjwm5c052j4uu1zet5o63gm2wh.png)
Explanation:
Given: A box contains 15 large marbles and 11 small marbles. Each marble is either green or white. 8 of the large marbles are green, and 5 of the small marbles are white.
To find: probability that a marble randomly selected is small or green
Solution:
Total number of marbles =
![15+11=26](https://img.qammunity.org/2022/formulas/mathematics/college/nskm7dt11ol9w43cajgakofnfx5umaejau.png)
Number of small marbles that are white = 5
Also, each marble is either green or white.
So,
Number of small marbles that are green =
![11-5=6](https://img.qammunity.org/2022/formulas/mathematics/college/uxey6bpxny5uhiuqbb90r8nsdasuabnao7.png)
Total number of green marbles = Number of large marbles that are green + Number of small marbles that are green
=
![8+6=14](https://img.qammunity.org/2022/formulas/mathematics/college/9dptvk8qy1lv4yauk1k1yy3qmo3hd2fptb.png)
Probability = Number of favorable outcomes ÷ Total number of outcomes
Let E denotes the event that a marble selected is small.
Let F denotes the event that a marble selected is green.
P(E) = Number of small marbles ÷ Total number of marbles
=
![(11)/(26)](https://img.qammunity.org/2022/formulas/mathematics/college/7ce6ufi0i0lsqz254mggomcdo328whd4s8.png)
P(F) = Number of green marbles ÷ Total number of marbles
=
![(14)/(26)](https://img.qammunity.org/2022/formulas/mathematics/college/ixlt3gyruieimwzukm6ul80thjaljf09mn.png)
P(E∩F) =
![(6)/(26)](https://img.qammunity.org/2022/formulas/mathematics/college/lk1ix53s66fw9r5grm6rrj1p78g7d0f1u2.png)
Probability that it is small or green = P(E∪F)
= P(E) + P(F) -P(E∩F)
=
![(11)/(26)+(14)/(26)-(6)/(26)](https://img.qammunity.org/2022/formulas/mathematics/college/w2wpasy19uxkawj2u9pmxtis1fya6nwkgc.png)
![=(11+14-6)/(26) \\\\ =(19)/(26) \\\\=0.7308](https://img.qammunity.org/2022/formulas/mathematics/college/ufg36gfn6houb3pk51bfh8ohuca9a8ghdr.png)