Question

If the delay of the 10-bit adder is 1ns, the setup time, the hold time, and the propagation delay of the registers is 0.3 ns, 0.1 ns, and 0.2 ns, respectively. The minimum cycle time is ns_____.

Answer 1

1.6 ns

Step-by-step explanation:

Given data :

delay in 10-bit adder = 1ns

setup time = 0.3 ns

hold time = 0.1 ns

propagation delay = 0.2 ns

calculate the minimum cycle time

∑ delay + setup time + hold time + propagation delay

= 1 + 0.3 + 0.1 + 0.2

= 1.6 ns