Answer:
50.25 g of sulphur, S.
Step-by-step explanation:
Mass of Na₂SO₄ = 223 g
Mass of sulphur =?
Next we shall determine the molar mass of Na₂SO₄. This can be obtained as follow:
Molar mass of Na₂SO₄ = (23×2) + 32 + (16×4)
= 46 + 32 +64
= 142 g/mol
Mass of S in 142 g of Na₂SO₄ = 32 g
Finally, we shall determine the mass of S in 223 g of Na₂SO₄. This can be obtained as follow:
142 g of Na₂SO₄ contains 32 g of S.
Therefore, 223 g of Na₂SO₄ will contain = (223 × 32) / 142 = 50.25 g of S.
Thus, 223 g of sodium sulfate, Na₂SO₄ contains 50.25 g of sulphur, S.