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In order to cool a cylindrical steel rod of diameter D, length L and uniform temperature T1, it is placed in a well-mixed water bath at initial temperature T0 and volume V0. The heat transfer coefficient between the steel rod surface and the water is h1. Assume the specific heat, density and conductivity of the steel rod and water are known and constant. Write down heat transfer differential V1, P1, T1 equation and boundary and initial conditions for temperature distribution in both steel rod and water bath

User Ismaelsow
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Answer:

attached below

Step-by-step explanation:

Cylindrical steel rod : diameter ( D ) , length L, uniform temperature T

Initial temp of water : To, heat transfer coefficient between steel rod surface and water : h1

The energy balance equation can be written as :

Rate of convectional heat loss = Rate of decrease in internal energy with respect to time

cp = heat capacity of body, v = volume , р = density of body

attached below is the heat transfer differential equation and boundary and initial conditions

In order to cool a cylindrical steel rod of diameter D, length L and uniform temperature-example-1
User Ocodo
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