Question

In an effort to be the star of the half-time show, the majorette twirls a highly unusual baton made up of four mases fastened to the ends of light rods. Each rod is 1.0 m lone. Find the moment of inertia of the system about an axis perpendicular to the page and passing through the point where the rods cross.

Answer 1

"0.25 kg-m²" is the appropriate answer.

Step-by-step explanation:

The diagram of the question is missing. Find the attachment of the diagram below.

According to the diagram, the values are:

m₁ = 0.2

m₂ = 0.3

m₃ = 0.3

m₄ = 0.2

d₁ = d₂ = d₃ = d₄ = 0.5 m

As we know,

The moment of inertia is:

⇒
`I=\Sigma M_id_i^2`

then,

⇒
`I=m_1d_1^2+m_2d_2^2+m_3d_3^2+m_4d_4^2`

⇒
`=d^2(m_1+m_2+m_3+m_4)`

On substituting the values, we get

⇒
`=0.5^2* (0.2+0.3+0.3+0.2)`

⇒
`=0.25* 1`

⇒
`=0.25 \ Kg-m^2`