Question

The gage pressure measured as 2.2 atm, the absolute pressure of gas is 3.2 bar. Please determine the local atmospheric pressure in kPa.

Answer 1

`97.085\ \text{kPa}`

Step-by-step explanation:

`P_(g)` = Gauge pressure = 2.2 atm =
`2.2* 101325=222915\ \text{Pa}`

`P_(abs)` = Absolute pressure =
`3.2\ \text{bar}=3.2* 10^5\ \text{Pa}`

`P_(atm)` = Local atmospheric pressure

Absolute pressure is given by

`P_(abs)=P_(atm)+P_g\\\Rightarrow P_(atm)=P_(abs)-P_g\\\Rightarrow P_(atm)=3.2* 10^5-222915\\\Rightarrow P_(atm)=97085\ \text{Pa}=97.085\ \text{kPa}`

The local atmospheric pressure is
`97.085\ \text{kPa}`.