Question

A chemist prepares a solution of mercury(I) chloride by measuring out of mercury(I) chloride into a volumetric flask and filling the flask to the mark with water. Calculate the concentration in of the chemist's mercury(I) chloride solution. Be sure your answer has the correct number of significant digits.

Answer 1

The given question is incomplete. The complete question is:

A chemist prepares a solution of mercury(I) chloride
`Hg_2Cl_2` by weighing out 0.537 mg of mercury(I) chloride into a 400. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in g/dL of the chemist's mercury(I) chloride solution. Round your answer to 3 significant digits

Answer: The concentration in g/dL of the chemist's mercury(I) chloride solution is
`1.34* 10^(-4)`

Step-by-step explanation:

Concentration of a solution is defined as how many grams of solute in=s dissolved in a particular amount of solvent.

Given : mass of mercury (I) chloride = 0.537 mg =
`5.37* 10^(-4)g`
`(1mg=0.001g)`

Volume of solution = 400 ml = 4 dL (1ml=0.01dL)

Thus concentration of mercury (I) chloride in g/dL is =
`(5.37* 10^(-4)g)/(4dL)=1.34* 10^(-4)g/dL`

The concentration in g/dL of the chemist's mercury(I) chloride solution is
`1.34* 10^(-4)`