Question

if you stop at random in front of an animal exhibit,What is the probability that you will be looking at monkeys? I put the table chart below

Answer 1

1/10

Explanation:

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| animals | percent of animals |

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| goats | 16% |

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| camels | 4% |

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| giraffes | 6% |

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| llamas | 6% |

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| deer | 1% |

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| monkeys | 10% |

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| birds | 27% |

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| reptiles | 14% |

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| bears | 16% |

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( sorry if the table above isnt 100% right or straight ^ )

first you add up all the percents of how much animals are in this exhibit

16 + 4 + 6 + 6 + 1 + 10 + 27 + 14 + 16

= 100 %

then since we are looking for the probability of stopping in front of the monkeys, we take that 100 we got earlier and get the 10% of monkeys from our table

10/100

but since there isnt a 10/100 on the answers we look for something that equals to 10/100 and 1/10 does since you can just times both the 1 and 10 to equal the 10 and 100 you were looking for

1/10

making 1/10 your answer!

hope this helps! and if you need anymore help on this math question just ask me :)