Factor completely 4x^2+20x A: 4(x^2+5x) B: x(4x*20) C: 4x(x+5) D: prime

asked Nov 26, 2022 231k views

3 votes

Factor completely 4x^2+20x

A: 4(x^2+5x)
B: x(4x*20)
C: 4x(x+5)
D: prime

by Ataur

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5 votes

Answer:

4x(x+5)

Explanation:

factor out the 4x out of the 4x^2

4.7k points

2 votes

C.

4x can go into both terms. So you left with 4x(x+5)

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