Help me please and have a good day

QAmmunity.org

My account
Edit my Profile
Private messages
My favorites

Ask a Question
Questions
Tags
Categories
Ask a Question

GnomeDePlume asked Sep 17, 2023

406,968 views

28 votes

Help me please and have a good day

Mathematics
high-school

GnomeDePlume asked Sep 17, 2023

by GnomeDePlume

2.8k points

0 Comments

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Your answer

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

1 Answer

20 votes

Answer:

D)
$x = (8)/(3) \: or \: x = - (5)/(2)$

Explanation:

$6 {x}^(2) - x - 40 = 0 \\ 6 {x}^(2) - 16x + 15x - 40 = 0 \\ 2x(3x - 8) + 5(3x - 8) = 0 \\ (3x - 8)(2x + 5) = 0 \\( 3x - 8)(2x + 5) = 0 \\ 3x - 8 = 0 \: \: \: \: or \: \: \: 2x + 5 = 0 \\ x = (8)/(3) \: \: \: or \: \: \: x = - (5)/(2)$

A Mehmeto answered Sep 22, 2023

by A Mehmeto

3.3k points

0 Comments

Your comment on this answer:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Ask a Question

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers

0 Comments

Your comment on this question:

Your answer

1 Answer

0 Comments

Your comment on this answer:

Other Questions