Final answer:
To react with 4.80 g of oxygen to produce carbon dioxide at STP, 6.724 liters of carbon monoxide are required, as per the stoichiometry of the balanced reaction.
Step-by-step explanation:
The question asks how many liters of carbon monoxide at STP (standard temperature and pressure) are needed to react with 4.80 g of oxygen gas to produce carbon dioxide, according to the chemical equation 2CO(g) + O2(g) = 2CO2(g). First, we must convert the mass of oxygen to moles using the molar mass of O2, which is 32.00 g/mol. 4.80 g O2 × (1 mol O2/32.00 g) = 0.15 mol O2. Now, according to the balanced chemical equation, the mole ratio of CO to O2 is 2:1, so 0.15 mol O2 x (2 mol CO/1 mol O2) = 0.30 mol CO. At STP, 1 mole of a gas occupies 22.414 L. Therefore, the volume of CO needed is 0.30 mol × 22.414 L/mol = 6.724 L of CO.