Question

Helppppp Asappppppppp

Answer 1

`\underline{1}Zn +\underline{ 2}HCL\to \underline{1}ZnCl_2+\underline{1}H_2`

Step-by-step explanation:

Here we need to balance the given reaction. The reaction is ,

`\underline{\quad} Zn +\underline{\quad}HCl \to \underline{\quad}ZnCl_2+\underline{\quad}H_2`

Firstly let's make a table here to see the number of elements in LHS and RHS as ,

`\boxed{\begin{tabular}c LHS & RHS \\\\\cline{1-2}\\\\ Zn = 1 & Zn = 1 \\\\ H =1$*$2=2& H = 2 \\\\ Cl =1$*$2=2 & H =2\end{tabular}}`

• We just need to multiply 2 to HCl on LHS in order to balance the equation. Therefore,

Our final reaction is,

`\underline{1}Zn +\underline{ 2}HCL\to \underline{1}ZnCl_2+\underline{1}H_2`

This is our required answer!