Question

Help !!! Compare the average rate of change of the two functions below. Which function has the greater average rate of change over the interval [1, 2] ??

Function A: g(x)=x^2+4x−8

Function B: h(x)=x^2−3x+6



Function A has the greater average rate of change over the interval [1, 2].



The two function have the same average rate of change over the interval [1, 2].



Function B has the greater average rate of change over the interval [1, 2].

Answer 1

Function A, g(x) = x^2 + 4x - 8, has a greater average rate of change over the interval [1, 2] since its average rate of change is 7, while function B's average rate of change is zero.

Step-by-step explanation:

To compare the average rate of change of functions A and B over the interval [1, 2], we calculate the average rate for each function using the formula:

Average Rate of Change = ∆y / ∆x = (f(2) - f(1)) / (2 - 1)

For Function A, g(x) = x^2 + 4x - 8:

g(2) = 2^2 + 4(2) - 8 = 4

g(1) = 1^2 + 4(1) - 8 = -3

So the average rate of change for A is (4 - (-3)) / (2 - 1) = 7.

For Function B, h(x) = x^2 - 3x + 6:

h(2) = 2^2 - 3(2) + 6 = 4

h(1) = 1^2 - 3(1) + 6 = 4

Therefore, the average rate of change for B is (4 - 4) / (2 - 1) = 0.

The function A has a greater average rate of change over the interval [1, 2] compared to function B, which has an average rate of change of zero.

Answer 2

Answer: I don’t know what it is but did you get the answer if so please

Step-by-step explanation:

help me