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What is an equation in point-slope form of the line that passes through (-7.1) and (-3.9)?

User Joao Leal
by
7.8k points

1 Answer

6 votes

Answer:


y-1=2(x+7)

Explanation:

Point-slope form:
y-y_1=m(x-x_1) where a given point is
(x_1,y_1) and the slope is
m

1) Find the slope of the line (m)

Slope =
(y_2-y_1)/(x_2-x_1) where the given points are
(x_1,y_1) and
(x_2,y_2)

Plug in the points (-7,1) and (-3,9)


= (9-1)/(-3-(-7))\\= (8)/(-3+7)\\= (8)/(4)\\= 2

Therefore, the slope of the line is 2. Plug 2 into the equation as m:


y-y_1=2(x-x_1)

2) Plug one of the given points into the equation

We plan either plug in (-7,1) or (-3,9) and it would work either way. Below you can see the equation plugging in the point (-7,1):


y-1=2(x-(-7))\\y-1=2(x+7)

I hope this helps!

User Mbelsky
by
8.4k points

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