Question

A source charge generates an electric field of 1236 N/C at a distance of 4 m. What is the magnitude of the source charge? (Use k=) 2. 2 µC 680 µC 2. 2 C 680 C.

Answer 1

Hi there!

The equation for the electric field of a point charge is given by:

`E = (kq)/(r^2)`

E = Electric Field (N/C)
k = Coulomb's Constant

r = distance (m)

We can rearrange to solve for 'q':'

`q^2 = (Er^2)/(k)\\\\q = \sqrt{(Er^2)/(k)}`

Plug in the values and solve:

`q = \sqrt{((1236)(4^2))/((8.99*10^9))} = \boxed{0.00148 C}`