Question

2. How many joules of heat are required to heat 237 g of lithium fluoride (specific heat = 1.56

joules/g®) from 21.3°C to 44.5°C? *
(1 Point)
350,439.10 joules
8,577.50 joules
24,327.58 joules
6.55 joules

Answer 1

Answer: 8,577.50

Explanation: subtract final temp from initial temp = 23.2 the multiply by grams = 5498.4 then multiply by J = 8,577.504

Answer 2

The answer is 24,327.58 joules