Question

1. A gas has a volume of 140L at 37 ºC and 620 kpa pressure. Calculate its volume at STP.

2. A helium balloon is filled to 2.5 L at 290 K. Outside, on a cold winter day, the balloon shrivels to 2.2 L. What is the outside temp in Kelvin?

3. What is the percent YIELD if 4.65g of copper (Cu) is actually produced when 1.87g of aluminum (Al) react with an excess of copper(II) sulfate (CuSO4)?

2Al + 3CuSO4 ____________ Al2(SO4)3 + 3Cu

Answer 1

1. Volume as STP = 755 L

2. Outside temperature = 255 K

3. Percentage yield = 70.5%

Step-by-step explanation:

1. At STP, pressure = 101.3 kpa, temperature = 0°C or 273.15 K

Using the general gas equation :

P1V1/T1 = P2V2/T2

P1 = 620 kpa

V1 = 140 L

T1 = 37°C or (273.15 + 37) K = 310.15 K

P2 = 101.3 kpa

V2 = ?

T2 = 273.15 K

V2 = P1V1T2/P2T1

V2 = 620 × 140 × 273.15 / 101.3 × 310.15

V2 = 755 L

2. Using Charles' gas law:

V1/T1 = V2/T2

V1 = 2.5 L

T1 = 290 K

V2 = 2.2 L

T2 = ?

T2 = V2T1/VI

T2 = 2.2 × 290 / 2.5

T2 = 255 K

3. Equation of reaction : 2 Al + 3 CuSO4 ---> Al2 (SO4)3 + 3 Cu

From equation of the reaction, 2 moles of Al produces 3 moles of Cu

Molar mass of Al = 27 g; Molar mass of Cu = 63.5 g

2 moles of Al = 2 × 27 g = 54 g; 3 moles of Cu = 3× 63.5 = 190.5 g

54 g of Al produces 190.5 g of Cu

1.87 g of Al will produce 190.5/54 × 1.87 g of Cu = 6.60 g of Cu

Percentage yield = actual yield /theoretical yield × 100%

Percentage yield = 4.65/6.60 × 100%

Percentage yield = 70.5%