Question

The circle below is centered at the point (8, 4) and has a radius of length 4. What is its equation?

Answer 1

(x-8)^2 + (y-4)^2 = 16

Explanation:

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Answer 2

(x-8)^2 + (y-4)^2 = 16

Explanation:

Standard equation of a circle is expressed as;

(x-a)^2 + (y-b)^2 = r^2

(a, b) is the centre

r is the radius

Given

Centre (8, 4)

r = 4

Substitute

(x-8)^2 + (y-4)^2 = 4^2

(x-8)^2 + (y-4)^2 = 16

This gives the required equation