Answer:
(a) 150 N
(b) 15.62 N
(c) 8.54 N
(d) 50 N
Step-by-step explanation:
From the question above,
(a) F' = F₂-F₁
Where F' = Result force, F₁ = 50 N, F₂ = 200 N
Therefore,
F' = 200-50
F' = 150 N
(b) F' = √(F₁²+F₂²)
Where F₁ = 10 N, F₂ =12 N
F' = √(10²+12²)
F' = √(100+144)
F '= √(244)
F =15.62 N
(c)
F' = √[(F₁+F₂)²+F₃²]
Where F₁ = 6 N, F₂ = 2 N, F₃ = 3 N.
Therefore,
F' = √[(6+2)²+3²)
F' = √(8²+3²)
F' = √(64+9)
F' = √(73)
F' = 8.54 N.
(d)
F' = √[(F₁+F₂)²+(F₃+F₄)²]
Where F₁ = 20 N, F₂ = 10 N, F₃ = 20 N, F₄ = 20 N
F' = √[(20+10)²+(20+20)²]
F' = √[(30)²+(40)²]
F' = √[900+1600]
F' = √[2500]
F' = 50 N