Answer:
5cm
Explanation:
Given
Height of the pole = 4m = opposite
Angle of elevation = 58 degrees
Required
length of shadow(hypotenuse)
Using the trig identity
Sin theta = opp/hyp
Sin 58 = 4/x
x = 4/sin58
x = 4/0.8480
x = 4.71cm
x ≈ 5cm
Hence the length of the shadow is 5cm to the nearest cm