Question

find to the nearest cm the length of a shadow of a 4m flag pole when the elevation of the sun is 58°​

Answer 1

5cm

Explanation:

Given

Height of the pole = 4m = opposite

Angle of elevation = 58 degrees

Required

length of shadow(hypotenuse)

Using the trig identity

Sin theta = opp/hyp

Sin 58 = 4/x

x = 4/sin58

x = 4/0.8480

x = 4.71cm

x ≈ 5cm

Hence the length of the shadow is 5cm to the nearest cm