Question

A tank of gas is found to exert 8.6 atm at 38°C. What would be the required

temperature to change the pressure to standard pressure?

Answer 1

36.2 K

Step-by-step explanation:

Step 1: Given data

• Initial pressure of the gas (P₁): 8.6 atm

• Initial temperature of the gas (T₁): 38°C

• Final pressure of the gas (P₂): 1.0 atm (standard pressure)

• Final temperature of the gas (T₂): ?

Step 2: Convert T₁ to Kelvin

We will use the following expression.

K = °C +273.15

K = 38 °C +273.15 = 311 K

Step 3: Calculate T₂

We will use Gay Lussac's law.

P₁/T₁ = P₂/T₂

T₂ = P₂ × T₁/P₁

T₂ = 1.0 atm × 311 K/8.6 atm = 36.2 K