Answer:

Explanation:
(8,2) (2,1)
First, you will need to find the gradient (or the m value in
)

y2=1
y1=2
x2=2
x1=8
Now we can plug in these values to get the m value.

Because the numerator and the denoinator will be negative, we needed to divide them to get a positive fraction.

Now we need to find the line of the equation using the following equation:

Now plug in the values using x1 and y1.

We can use the distributive property to distribute the
.

Lastly, we can add 2 to both sides to cancel out the -2 on the left to give us our equation.
