Given:
Number of girls = 10
Number of boys = 15
To find:
The probability that the first, second and third place winners will be boys.
Solution:
Total number of boys and girls:
![10+15=25](https://img.qammunity.org/2022/formulas/mathematics/high-school/pb2sr9im16ol44yz2y42ql6vxa21kc6xi0.png)
The probability that the first place winner will be a boy is
![P(\text{Boy at first place})=(15)/(25)](https://img.qammunity.org/2022/formulas/mathematics/high-school/hn1rh30nc6b7soojkcikgbtmkn9pr9hv2v.png)
Now, the remaining number of boys is 14. So, the probability that the first place winner will be a boy is
![P(\text{Boy at second place})=(14)/(24)](https://img.qammunity.org/2022/formulas/mathematics/high-school/9852azs55o2f0cax2tryud66ewzw4pd65r.png)
Now, the remaining number of boys is 13. So, the probability that the first place winner will be a boy is
![P(\text{Boy at third place})=(13)/(23)](https://img.qammunity.org/2022/formulas/mathematics/high-school/453o03smj2rlext5kpbg9417btb8lhf8b1.png)
The probability that the first, second and third place winners will be boys is
![P(BBB)=(15)/(25)* (14)/(24)* (13)/(23)](https://img.qammunity.org/2022/formulas/mathematics/high-school/pjx7h6wvrgiqmukel87wy2ybsp07eyrbeu.png)
![P(BBB)=(3)/(5)* (7)/(12)* (13)/(23)](https://img.qammunity.org/2022/formulas/mathematics/high-school/wi8jfrdznzlyo270equ3r8mhfrm5pqd9bu.png)
![P(BBB)=(1)/(5)* (7)/(4)* (13)/(23)](https://img.qammunity.org/2022/formulas/mathematics/high-school/r843b2dl751hkr6h52exnllzxenz1q7psq.png)
![P(BBB)=(91)/(460)](https://img.qammunity.org/2022/formulas/mathematics/high-school/novimq6nvpe7qu6t5c54oyi79qnrfgqsg1.png)
Therefore, the probability that the first, second and third place winners will be boys is
.