Question

Calculate the period of oscillation of a pendulum with a small amplitude whose length is 2.5 meters

Answer 1

T = 3.17 s

Step-by-step explanation:

Given that,

The length of the pendulum, l = 2.5 m

We know that the period of oscillation of the pendulum is given by :

`T=2\pi \sqrt{(l)/(g)}`

Where

g is the acceleration due to gravity

`T=2\pi \sqrt{(2.5)/(9.8)}\\\\T=3.17\ s`

So, the period of oscillation is equal to 3.17 s.