1 Answer

David Siro · Answer 1 · 2022-03-23T04:36:17+0000

Answer:

$15887.55\ \text{gallons}$

Explanation:

d = Diameter of pool = 26 ft

r = Radius =
$(d)/(2)=(26)/(2)=13\ \text{ft}$

h = Height of pool = 4 ft

Volume of the pool is

$V=\pi r^2h=\pi* 13^2* 4\\\Rightarrow V=2123.72\ \text{ft}^3$

Converting to gallons

$1\ \text{ft}^3=7.481\ \text{gallons}\\\Rightarrow 2123.72\ \text{ft}^3=2123.72* 7.481\\ =15887.55\ \text{gallons}$

So, the gallons of water required to fill the pool is
$15887.55\ \text{gallons}$ .

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