Answer:
Explanation:
The standard form of equation of a circle is expressed as;
x^2+y^2+2gx+2fy+c = 0
The centre is at (-g, -f)
Given the equation'
9x²+9y²+18x-12+10=0
Divide through by 9
9x²/9+9y²/9+18x/9-12y/9+10/9=0
x^2+y^2+2x-4/3 y + 10/9 = 0
Compare
2gx = 2x
g = 1
2fy = -4/3 y
2f = -4/3
f = -4/6
f = -2/3
The centre is (-(-2/3), -1) = (2/3, -1)
for the radius
r = √f²+g²-c
r =√(-2/3)²+1²-10
r =√4/9 - 9
r = √(4-81)/9
r = √-77/9