Answer:
Explanation:
for 1 they give us an angle and the side next to that angle.. or the Adjacent side and they want to know the Opposite side from the angle sooo let's use ..
SOH CAH TOA
hmm TOA seems good , it's got the adj and Opp in it ,
Tan(Ф) = Opp / Adj
Tan(67) = Opp / 26
26 * Tan(67) = Opp
61.2521 = Opp
61.3 ( rounded to nearest 10th ) does this seem big to you? well it should be quite a bit bigger than the 25 on the base, seems about right to me
for 2 they give us one angle, 48 , and one side, 35 , that is opposite from that angle, and ask what is the Hyp. So find a trig function that has those pieces in it. SOH seems good
sin(Ф) = Opp / Hyp
sin(48) = 35 / Hyp
Hyp = 35 / sin(48)
Hyp = 47.0971 ( and that seems about right for the Hypotenuse )
x = 47.1 ( rounded to the nearest 10th )
for 3 they are asking us to imagine a triangle, I'll draw it and attach it as a picture. Looking at the picture helps a lot, we can see we have the angle and the adj side and want to find the Opposite side of that big triangle. sooo use TOA , it's got those pieces in it
Tan(17) = Opp / 200
200*Tan(17) = Opp
61.1461 =Opp
so the height of the radio mast is 61.1 meters ( rounded to nearest 10th )
Does this seem a bit easier when you think about how the parts of the trig functions fit on the triangles? :) ask if you have any questions