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In ΔCDE, the measure of ∠E=90°, the measure of ∠C=70°, and DE = 12 feet. Find the length of CD to the nearest tenth of a foot

2 Answers

4 votes

Answer:

12.8

Explanation:

User Michele Mariotti
by
4.3k points
5 votes

Answer:


CD = 4.4ft

Explanation:

Given


DE = 12


\angle C = 70^\circ

Required

Find CD

This question is represented with the attached triangle

To solve CD, we make use of tan formula.


tan(70) = (DE)/(CD)

Substitute 12 for DE


tan(70) = (12)/(CD)

Make CD the subject


CD = (12)/(tan(70))


CD = (12)/(2.7475)


CD = 4.4ft --- approximated

In ΔCDE, the measure of ∠E=90°, the measure of ∠C=70°, and DE = 12 feet. Find the-example-1
User Dmitry Kaltovich
by
4.2k points