Question

In ΔBCD, the measure of ∠D=90°, the measure of ∠B=71°, and DB = 67 feet. Find the length of BC to the nearest tenth of a foot.

Answer 1

BC = 205.8 feet

Explanation:

Please see attached photo

From the attached photo:

Angle B = 71°

Adjacent = BD = 67 feet

Hypothenus = BC = x

The value of x can be obtained as follow:

Cos B = Adjacent / Hypothenus

Cos 71 = 67 / x

0.3256 = 67 / x

Cross multiply

0.3256 × x = 67

Divide both side by 0.3256

x = 67 / 0.3256

x = 205.8 feet

Therefore BC = 205.8 feet