Question

Please answer :( im very lonely and im bad at maths so do it for me :(((

Answer 1

Explanation:

First you need to calculate the entire length (in meters) of the metal used in the gate, then multiple the length by 2.5 kg per meter

Break it into parts.......

four pieces on along the outside is just the perimeter of a rectangle

P = 2( L + H) both sides and the top and bottom

the two crossing metal pieces are just the hypotenuse of a right triangle and since we have two pieces of metal

a² + b² = c² or L² + H² = Hyp² solving for the htpotenuse

Hyp =
`\sqrt[]{L^2 + H^2}`

so the total length of the gate metal is

P = 2( L + H) plus 2 Hyp =
`\sqrt[]{L^2 + H^2}`

= 2( 12 + 5) + 2 [ √(12² + 5²) ]

= 34 + 2 [ √( 144 + 25) ]

= 34 + 2 ( √169)

= 34 + 2( 13)

= 34 + 26

= 60 meters of gate metal metal weighs 2.5 kg per meter

Total weight equals 60 meters times 2.5 kg per meter

Total weight = 60 (2.5) = 150 kg