Question

write an equation of a line passing through the point (-4,11) and perpendicular to the line 4x + 5y = -45

Answer 1

y = 5/4x - 6

Explanation:

First, put 4x + 5y= -45​ in y = mx + b form

4x + 5y= -45​

5y = -4x - 45

y = -4/5x - 9

So, the slope is -4/5. Perpendicular lines have a opposite reciprocal slope, so the line's slope will be 5/4 right so to find the equation of the perpendicular line in this question, plug in the slope and given point into y = mx + b, and solve for b

y = mx + b

-11 = 5/4(-4) + b

-11 = -5 + b

-6 = b

so you should Plug in b and the slope into y = mx + b

y = 5/4x - 6

So, the equation is y = 5/4x - 6

if this doesn't make sense i don't know what will